What is the molarity of a solution containing 9 0 moles of solute in 500 0 mL of solution?

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What is the molarity of 500 ml of a solution containing?

Explanation: Molarity of a solution is the mumber of moles per litre. You have 0.75 moles in 500 ml. Therefore, you have 0.75 moles / 0.5 litre, which is 1.5 moles per liter, or 1.5 Molar.

5 mol L−1.

How many moles of solute are there in 500ml?

0.5 moles of a solute is present in 500 ml of the solution.

What is the molarity of solution containing 5 moles of solute in 250 ml of solution?

The molarity of the solution is 5.1 mol/L .

What is the molarity of a 500ml solution containing 249?

What is the molarity of a 500 mL solution containing 249 g of KI? Then, M (KI) = 39+127 = 166 (g/mol); n (KI)= m(KI) / M(KI) = 249 / (39+127) = 249 / 166 = 1.50 (mol);

What is the molarity of a solution containing 20 grams?

Calculate the molarity of the solution. 20 gr of NaOH correspond to 0.5 moles which are contained in 0.5 liter of solution. In one liter of solution there will be (2)(0.5) = 1 mole and thus the solution is 1 M.

What will be the molarity of 30 mL of 0.5 m?

30 mL of 0.5 M H2SO4 contain = vwX30 = 0.015 mol 1000 Volume of diluted solution = 500 mL = 0.500 L Since 30 mL of 0.5 M H2SO4 is diluted to 0.500 L, number of moles of H2SO4 = 0.015 mol From formula, 0.015 mol = 0.03 M Molarity of solution = 0.500 L inic 0024 M.

What is the molarity of a 450 mL solution containing 5g of NaOH?

=0.277777777778=0.28(approx.)

What is the molarity of a 250 mL solution containing .075 moles of NaOH?

250 ml of solution therefore contains 0.25 x 3 = 0.75 moles of NaOH. The molar mass of NaOH is 39.9971 g/mol, so 250 ml of this solution contains 0.75 x 39.9971 = 29.99 g, or if you round it up 30.0 g.

How do I calculate molarity?

To calculate the molarity of a solution, you divide the moles of solute by the volume of the solution expressed in liters. Note that the volume is in liters of solution and not liters of solvent. When a molarity is reported, the unit is the symbol M and is read as “molar”.

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What is the molarity of a 0.30 liter solution containing 0.50 moles of nac1?

concentration=[NaCl(aq)]=0.50⋅mol0.30⋅L=1.67⋅mol⋅L−1 .

Is 0.01 mole of solute is present in 500 mL of solution its molarity is?

Molarity = 0.01/0.5=0.02 mol per litre. Q3.

What is the molarity of a solution that contains 5.0 moles of solute in 2.00 Litres of solution?

M=5mol2L=2. 5mol/L. 5 m o l / L . Hence, the correct option is A that is 2.5M .

What is the molarity of a solution with 10 moles of solute and 100 Litre volume?

Answer: Explanation: Molarity = 10/100 = 0.1 molar.

What is the molarity of a 2.0 l sodium?

Explanation: We take the quotient, 10.0⋅g40.00⋅g⋅mol−12.0⋅L=0.125⋅mol⋅L−1 .