How many moles of glucose C6H12O6 are present in 5 4 g?

How many moles of glucose C6H12O6 are present in 5.4 g?

So, 5.40 g= 5.4/180=0.03moles.

How many moles of glucose does C6H12O6?

There are 2 moles of C6H12O6 in 300 g C6H12O6 , rounded to one significant figure.

How many moles of glucose C6H12O6 are present in 540g?

The number of moles in 540 gm is 3 moles.

How many moles of glucose are present in 540 grams of glucose?

So, 540 g= 540/180=3 moles.

How many moles of glucose are in 5 grams?

So 1 mole of glucose weighs 180g. There are 6.02 x 1023 particles in a mole so 180 g of glucose must contain 6 x 6.02 x 1023 carbon atoms. This equals 3.61 x 1024 carbon atoms. So 5g glucose contains 2 x 1022 x 5 = 1023 carbon atoms.

How many moles of glucose are present in 720g of glucose?

3 moles of glucose are present in 720 gram of glucose.

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